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Description
tab: English
<p>You are given an array <code>prices</code> where <code>prices[i]</code> is the price of a given stock on the <code>i<sup>th</sup></code> day.</p>
<p>You want to maximize your profit by choosing a <strong>single day</strong> to buy one stock and choosing a <strong>different day in the future</strong> to sell that stock.</p>
<p>Return <em>the maximum profit you can achieve from this transaction</em>. If you cannot achieve any profit, return <code>0</code>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> prices = [7,1,5,3,6,4]
<strong>Output:</strong> 5
<strong>Explanation:</strong> Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> prices = [7,6,4,3,1]
<strong>Output:</strong> 0
<strong>Explanation:</strong> In this case, no transactions are done and the max profit = 0.
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= prices.length <= 10<sup>5</sup></code></li>
<li><code>0 <= prices[i] <= 10<sup>4</sup></code></li>
</ul>
---
[submissions](https://leetcode.com/problems/best-time-to-buy-and-sell-stock/submissions/) | [solutions](https://leetcode.com/problems/best-time-to-buy-and-sell-stock/solutions/)
tab: 中文
<p>给定一个数组 <code>prices</code> ，它的第 <code>i</code> 个元素 <code>prices[i]</code> 表示一支给定股票第 <code>i</code> 天的价格。</p>
<p>你只能选择 <strong>某一天</strong> 买入这只股票，并选择在 <strong>未来的某一个不同的日子</strong> 卖出该股票。设计一个算法来计算你所能获取的最大利润。</p>
<p>返回你可以从这笔交易中获取的最大利润。如果你不能获取任何利润，返回 <code>0</code> 。</p>
<p> </p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>[7,1,5,3,6,4]
<strong>输出：</strong>5
<strong>解释：</strong>在第 2 天（股票价格 = 1）的时候买入，在第 5 天（股票价格 = 6）的时候卖出，最大利润 = 6-1 = 5 。
注意利润不能是 7-1 = 6, 因为卖出价格需要大于买入价格；同时，你不能在买入前卖出股票。
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>prices = [7,6,4,3,1]
<strong>输出：</strong>0
<strong>解释：</strong>在这种情况下, 没有交易完成, 所以最大利润为 0。
</pre>
<p> </p>
<p><strong>提示：</strong></p>
<ul>
<li><code>1 <= prices.length <= 10<sup>5</sup></code></li>
<li><code>0 <= prices[i] <= 10<sup>4</sup></code></li>
</ul>
---
[提交记录](https://leetcode.cn/problems/best-time-to-buy-and-sell-stock/submissions/) | [题解](https://leetcode.cn/problems/best-time-to-buy-and-sell-stock/solution/)
Solutions & Notes
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