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Description
tab: English
<p>Given a non-negative integer <code>x</code>, return <em>the square root of </em><code>x</code><em> rounded down to the nearest integer</em>. The returned integer should be <strong>non-negative</strong> as well.</p>
<p>You <strong>must not use</strong> any built-in exponent function or operator.</p>
<ul>
<li>For example, do not use <code>pow(x, 0.5)</code> in c++ or <code>x ** 0.5</code> in python.</li>
</ul>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> x = 4
<strong>Output:</strong> 2
<strong>Explanation:</strong> The square root of 4 is 2, so we return 2.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> x = 8
<strong>Output:</strong> 2
<strong>Explanation:</strong> The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>0 <= x <= 2<sup>31</sup> - 1</code></li>
</ul>
> [!tip]- Hint 1
>
> Try exploring all integers. (Credits: @annujoshi)
> [!tip]- Hint 2
>
> Use the sorted property of integers to reduced the search space. (Credits: @annujoshi)
---
[submissions](https://leetcode.com/problems/sqrtx/submissions/) | [solutions](https://leetcode.com/problems/sqrtx/solutions/)
tab: 中文
<p>给你一个非负整数 <code>x</code> ，计算并返回 <code>x</code> 的 <strong>算术平方根</strong> 。</p>
<p>由于返回类型是整数，结果只保留 <strong>整数部分 </strong>，小数部分将被 <strong>舍去 。</strong></p>
<p><strong>注意：</strong>不允许使用任何内置指数函数和算符，例如 <code>pow(x, 0.5)</code> 或者 <code>x ** 0.5</code> 。</p>
<p> </p>
<p><strong>示例 1：</strong></p>
<pre>
<strong>输入：</strong>x = 4
<strong>输出：</strong>2
</pre>
<p><strong>示例 2：</strong></p>
<pre>
<strong>输入：</strong>x = 8
<strong>输出：</strong>2
<strong>解释：</strong>8 的算术平方根是 2.82842..., 由于返回类型是整数，小数部分将被舍去。
</pre>
<p> </p>
<p><strong>提示：</strong></p>
<ul>
<li><code>0 <= x <= 2<sup>31</sup> - 1</code></li>
</ul>
> [!tip]- 提示 1
>
> Try exploring all integers. (Credits: @annujoshi)
> [!tip]- 提示 2
>
> Use the sorted property of integers to reduced the search space. (Credits: @annujoshi)
---
[提交记录](https://leetcode.cn/problems/sqrtx/submissions/) | [题解](https://leetcode.cn/problems/sqrtx/solution/)
Solutions & Notes
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