Project Notes

Pow(x, n)

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Description

tab: English
 
<p>Implement <a href="http://www.cplusplus.com/reference/valarray/pow/" target="_blank">pow(x, n)</a>, which calculates <code>x</code> raised to the power <code>n</code> (i.e., <code>x<sup>n</sup></code>).</p>
 
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
 
<pre>
<strong>Input:</strong> x = 2.00000, n = 10
<strong>Output:</strong> 1024.00000
</pre>
 
<p><strong class="example">Example 2:</strong></p>
 
<pre>
<strong>Input:</strong> x = 2.10000, n = 3
<strong>Output:</strong> 9.26100
</pre>
 
<p><strong class="example">Example 3:</strong></p>
 
<pre>
<strong>Input:</strong> x = 2.00000, n = -2
<strong>Output:</strong> 0.25000
<strong>Explanation:</strong> 2<sup>-2</sup> = 1/2<sup>2</sup> = 1/4 = 0.25
</pre>
 
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
 
<ul>
	<li><code>-100.0 &lt; x &lt; 100.0</code></li>
	<li><code>-2<sup>31</sup> &lt;= n &lt;= 2<sup>31</sup>-1</code></li>
	<li><code>n</code> is an integer.</li>
	<li>Either <code>x</code> is not zero or <code>n &gt; 0</code>.</li>
	<li><code>-10<sup>4</sup> &lt;= x<sup>n</sup> &lt;= 10<sup>4</sup></code></li>
</ul>
 
 
 
---
 
[submissions](https://leetcode.com/problems/powx-n/submissions/) | [solutions](https://leetcode.com/problems/powx-n/solutions/)
 
 
tab: 中文
 
<p>实现&nbsp;<a href="https://www.cplusplus.com/reference/valarray/pow/" target="_blank">pow(<em>x</em>, <em>n</em>)</a>&nbsp;，即计算 <code>x</code> 的整数&nbsp;<code>n</code> 次幂函数（即，<code>x<sup>n</sup></code><sup><span style="font-size:10.8333px"> </span></sup>）。</p>
 
<p>&nbsp;</p>
 
<p><strong class="example">示例 1：</strong></p>
 
<pre>
<strong>输入：</strong>x = 2.00000, n = 10
<strong>输出：</strong>1024.00000
</pre>
 
<p><strong class="example">示例 2：</strong></p>
 
<pre>
<strong>输入：</strong>x = 2.10000, n = 3
<strong>输出：</strong>9.26100
</pre>
 
<p><strong class="example">示例 3：</strong></p>
 
<pre>
<strong>输入：</strong>x = 2.00000, n = -2
<strong>输出：</strong>0.25000
<strong>解释：</strong>2<sup>-2</sup> = 1/2<sup>2</sup> = 1/4 = 0.25
</pre>
 
<p>&nbsp;</p>
 
<p><strong>提示：</strong></p>
 
<ul>
	<li><code>-100.0 &lt; x &lt; 100.0</code></li>
	<li><code>-2<sup>31</sup> &lt;= n &lt;= 2<sup>31</sup>-1</code></li>
	<li><code>n</code>&nbsp;是一个整数</li>
	<li>要么 <code>x</code> 不为零，要么 <code>n &gt; 0</code> 。</li>
	<li><code>-10<sup>4</sup> &lt;= x<sup>n</sup> &lt;= 10<sup>4</sup></code></li>
</ul>
 
 
 
---
 
[提交记录](https://leetcode.cn/problems/powx-n/submissions/) | [题解](https://leetcode.cn/problems/powx-n/solution/)

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