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Description
tab: English
<p>Given an array <code>nums</code> containing <code>n</code> distinct numbers in the range <code>[0, n]</code>, return <em>the only number in the range that is missing from the array.</em></p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [3,0,1]</span></p>
<p><strong>Output:</strong> <span class="example-io">2</span></p>
<p><strong>Explanation:</strong></p>
<p><code>n = 3</code> since there are 3 numbers, so all numbers are in the range <code>[0,3]</code>. 2 is the missing number in the range since it does not appear in <code>nums</code>.</p>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [0,1]</span></p>
<p><strong>Output:</strong> <span class="example-io">2</span></p>
<p><strong>Explanation:</strong></p>
<p><code>n = 2</code> since there are 2 numbers, so all numbers are in the range <code>[0,2]</code>. 2 is the missing number in the range since it does not appear in <code>nums</code>.</p>
</div>
<p><strong class="example">Example 3:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [9,6,4,2,3,5,7,0,1]</span></p>
<p><strong>Output:</strong> <span class="example-io">8</span></p>
<p><strong>Explanation:</strong></p>
<p><code>n = 9</code> since there are 9 numbers, so all numbers are in the range <code>[0,9]</code>. 8 is the missing number in the range since it does not appear in <code>nums</code>.</p>
</div>
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<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == nums.length</code></li>
<li><code>1 <= n <= 10<sup>4</sup></code></li>
<li><code>0 <= nums[i] <= n</code></li>
<li>All the numbers of <code>nums</code> are <strong>unique</strong>.</li>
</ul>
<p> </p>
<p><strong>Follow up:</strong> Could you implement a solution using only <code>O(1)</code> extra space complexity and <code>O(n)</code> runtime complexity?</p>
---
[submissions](https://leetcode.com/problems/missing-number/submissions/) | [solutions](https://leetcode.com/problems/missing-number/solutions/)
tab: 中文
<p>给定一个包含 <code>[0, n]</code> 中 <code>n</code> 个数的数组 <code>nums</code> ,找出 <code>[0, n]</code> 这个范围内没有出现在数组中的那个数。</p>
<ul>
</ul>
<p> </p>
<p><strong>示例 1:</strong></p>
<div class="example-block">
<p><strong>输入:</strong>nums = [3,0,1]</p>
<p><strong>输出:</strong>2</p>
<p><b>解释:</b><code>n = 3</code>,因为有 3 个数字,所以所有的数字都在范围 <code>[0,3]</code> 内。2 是丢失的数字,因为它没有出现在 <code>nums</code> 中。</p>
</div>
<p><strong>示例 2:</strong></p>
<div class="example-block">
<p><strong>输入:</strong>nums = [0,1]</p>
<p><strong>输出:</strong>2</p>
<p><b>解释:</b><code>n = 2</code>,因为有 2 个数字,所以所有的数字都在范围 <code>[0,2]</code> 内。2 是丢失的数字,因为它没有出现在 <code>nums</code> 中。</p>
</div>
<p><strong>示例 3:</strong></p>
<div class="example-block">
<p><strong>输入:</strong>nums = [9,6,4,2,3,5,7,0,1]</p>
<p><strong>输出:</strong>8</p>
<p><b>解释:</b><code>n = 9</code>,因为有 9 个数字,所以所有的数字都在范围 <code>[0,9]</code> 内。8 是丢失的数字,因为它没有出现在 <code>nums</code> 中。</p>
</div>
<p><strong>提示:</strong></p>
<ul>
<li><code>n == nums.length</code></li>
<li><code>1 <= n <= 10<sup>4</sup></code></li>
<li><code>0 <= nums[i] <= n</code></li>
<li><code>nums</code> 中的所有数字都 <strong>独一无二</strong></li>
</ul>
<p> </p>
<p><strong>进阶:</strong>你能否实现线性时间复杂度、仅使用额外常数空间的算法解决此问题?</p>
---
[提交记录](https://leetcode.cn/problems/missing-number/submissions/) | [题解](https://leetcode.cn/problems/missing-number/solution/)
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