Project Notes

Number of Digit One

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Description

tab: English
 
<p>Given an integer <code>n</code>, count <em>the total number of digit </em><code>1</code><em> appearing in all non-negative integers less than or equal to</em> <code>n</code>.</p>
 
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
 
<pre>
<strong>Input:</strong> n = 13
<strong>Output:</strong> 6
</pre>
 
<p><strong class="example">Example 2:</strong></p>
 
<pre>
<strong>Input:</strong> n = 0
<strong>Output:</strong> 0
</pre>
 
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
 
<ul>
	<li><code>0 &lt;= n &lt;= 10<sup>9</sup></code></li>
</ul>
 
 
 
> [!tip]- Hint 1
> 
> Beware of overflow.
 
 
---
 
[submissions](https://leetcode.com/problems/number-of-digit-one/submissions/) | [solutions](https://leetcode.com/problems/number-of-digit-one/solutions/)
 
 
tab: 中文
 
<p>给定一个整数 <code>n</code>，计算所有小于等于 <code>n</code> 的非负整数中数字 <code>1</code> 出现的个数。</p>
 
<p>&nbsp;</p>
 
<p><strong>示例 1：</strong></p>
 
<pre>
<strong>输入：</strong>n = 13
<strong>输出：</strong>6
</pre>
 
<p><strong>示例 2：</strong></p>
 
<pre>
<strong>输入：</strong>n = 0
<strong>输出：</strong>0
</pre>
 
<p>&nbsp;</p>
 
<p><strong>提示：</strong></p>
 
<ul>
	<li><code>0 &lt;= n &lt;= 10<sup>9</sup></code></li>
</ul>
 
 
 
> [!tip]- 提示 1
> 
> Beware of overflow.
 
 
---
 
[提交记录](https://leetcode.cn/problems/number-of-digit-one/submissions/) | [题解](https://leetcode.cn/problems/number-of-digit-one/solution/)

Solutions & Notes

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