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Description
tab: English
<p>Given an integer array <code>nums</code>, return <em>the maximum difference between two successive elements in its sorted form</em>. If the array contains less than two elements, return <code>0</code>.</p>
<p>You must write an algorithm that runs in linear time and uses linear extra space.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> nums = [3,6,9,1]
<strong>Output:</strong> 3
<strong>Explanation:</strong> The sorted form of the array is [1,3,6,9], either (3,6) or (6,9) has the maximum difference 3.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> nums = [10]
<strong>Output:</strong> 0
<strong>Explanation:</strong> The array contains less than 2 elements, therefore return 0.
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>
</ul>
---
[submissions](https://leetcode.com/problems/maximum-gap/submissions/) | [solutions](https://leetcode.com/problems/maximum-gap/solutions/)
tab: 中文
<p>给定一个无序的数组 <code>nums</code>,返回 <em>数组在排序之后,相邻元素之间最大的差值</em> 。如果数组元素个数小于 2,则返回 <code>0</code> 。</p>
<p>您必须编写一个在「线性时间」内运行并使用「线性额外空间」的算法。</p>
<p> </p>
<p><strong>示例 1:</strong></p>
<pre>
<strong>输入:</strong> nums = [3,6,9,1]
<strong>输出:</strong> 3
<strong>解释:</strong> 排序后的数组是 [1,3,6,9]<strong><em>, </em></strong>其中相邻元素 (3,6) 和 (6,9) 之间都存在最大差值 3。</pre>
<p><strong>示例 2:</strong></p>
<pre>
<strong>输入:</strong> nums = [10]
<strong>输出:</strong> 0
<strong>解释:</strong> 数组元素个数小于 2,因此返回 0。</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>
</ul>
---
[提交记录](https://leetcode.cn/problems/maximum-gap/submissions/) | [题解](https://leetcode.cn/problems/maximum-gap/solution/)
Solutions & Notes
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