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Description

tab: English
 
<p>Given a string <code>s</code> and a dictionary of strings <code>wordDict</code>, return <code>true</code> if <code>s</code> can be segmented into a space-separated sequence of one or more dictionary words.</p>
 
<p><strong>Note</strong> that the same word in the dictionary may be reused multiple times in the segmentation.</p>
 
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
 
<pre>
<strong>Input:</strong> s = &quot;leetcode&quot;, wordDict = [&quot;leet&quot;,&quot;code&quot;]
<strong>Output:</strong> true
<strong>Explanation:</strong> Return true because &quot;leetcode&quot; can be segmented as &quot;leet code&quot;.
</pre>
 
<p><strong class="example">Example 2:</strong></p>
 
<pre>
<strong>Input:</strong> s = &quot;applepenapple&quot;, wordDict = [&quot;apple&quot;,&quot;pen&quot;]
<strong>Output:</strong> true
<strong>Explanation:</strong> Return true because &quot;applepenapple&quot; can be segmented as &quot;apple pen apple&quot;.
Note that you are allowed to reuse a dictionary word.
</pre>
 
<p><strong class="example">Example 3:</strong></p>
 
<pre>
<strong>Input:</strong> s = &quot;catsandog&quot;, wordDict = [&quot;cats&quot;,&quot;dog&quot;,&quot;sand&quot;,&quot;and&quot;,&quot;cat&quot;]
<strong>Output:</strong> false
</pre>
 
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
 
<ul>
	<li><code>1 &lt;= s.length &lt;= 300</code></li>
	<li><code>1 &lt;= wordDict.length &lt;= 1000</code></li>
	<li><code>1 &lt;= wordDict[i].length &lt;= 20</code></li>
	<li><code>s</code> and <code>wordDict[i]</code> consist of only lowercase English letters.</li>
	<li>All the strings of <code>wordDict</code> are <strong>unique</strong>.</li>
</ul>
 
 
 
---
 
[submissions](https://leetcode.com/problems/word-break/submissions/) | [solutions](https://leetcode.com/problems/word-break/solutions/)
 
 
tab: 中文
 
<p>给你一个字符串 <code>s</code> 和一个字符串列表 <code>wordDict</code> 作为字典。如果可以利用字典中出现的一个或多个单词拼接出 <code>s</code>&nbsp;则返回 <code>true</code>。</p>
 
<p><strong>注意:</strong>不要求字典中出现的单词全部都使用,并且字典中的单词可以重复使用。</p>
 
<p>&nbsp;</p>
 
<p><strong>示例 1:</strong></p>
 
<pre>
<strong>输入:</strong> s = "leetcode", wordDict = ["leet", "code"]
<strong>输出:</strong> true
<strong>解释:</strong> 返回 true 因为 "leetcode" 可以由 "leet" 和 "code" 拼接成。
</pre>
 
<p><strong>示例 2:</strong></p>
 
<pre>
<strong>输入:</strong> s = "applepenapple", wordDict = ["apple", "pen"]
<strong>输出:</strong> true
<strong>解释:</strong> 返回 true 因为 "applepenapple" 可以由 "apple" "pen" "apple" 拼接成。
&nbsp;    注意,你可以重复使用字典中的单词。
</pre>
 
<p><strong>示例 3:</strong></p>
 
<pre>
<strong>输入:</strong> s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"]
<strong>输出:</strong> false
</pre>
 
<p>&nbsp;</p>
 
<p><strong>提示:</strong></p>
 
<ul>
	<li><code>1 &lt;= s.length &lt;= 300</code></li>
	<li><code>1 &lt;= wordDict.length &lt;= 1000</code></li>
	<li><code>1 &lt;= wordDict[i].length &lt;= 20</code></li>
	<li><code>s</code> 和 <code>wordDict[i]</code> 仅由小写英文字母组成</li>
	<li><code>wordDict</code> 中的所有字符串 <strong>互不相同</strong></li>
</ul>
 
 
 
---
 
[提交记录](https://leetcode.cn/problems/word-break/submissions/) | [题解](https://leetcode.cn/problems/word-break/solution/)
 
 

Solutions & Notes

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