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Description

tab: English
 
<p>Given an integer array <code>nums</code> where&nbsp;every element appears <strong>three times</strong> except for one, which appears <strong>exactly once</strong>. <em>Find the single element and return it</em>.</p>
 
<p>You must&nbsp;implement a solution with a linear runtime complexity and use&nbsp;only constant&nbsp;extra space.</p>
 
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> nums = [2,2,3,2]
<strong>Output:</strong> 3
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> nums = [0,1,0,1,0,1,99]
<strong>Output:</strong> 99
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
 
<ul>
	<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>
	<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>
	<li>Each element in <code>nums</code> appears exactly <strong>three times</strong> except for one element which appears <strong>once</strong>.</li>
</ul>
 
 
 
---
 
[submissions](https://leetcode.com/problems/single-number-ii/submissions/) | [solutions](https://leetcode.com/problems/single-number-ii/solutions/)
 
 
tab: 中文
 
<p>给你一个整数数组&nbsp;<code>nums</code> ,除某个元素仅出现 <strong>一次</strong> 外,其余每个元素都恰出现 <strong>三次 。</strong>请你找出并返回那个只出现了一次的元素。</p>
 
<p>你必须设计并实现线性时间复杂度的算法且使用常数级空间来解决此问题。</p>
 
<p>&nbsp;</p>
 
<p><strong>示例 1:</strong></p>
 
<pre>
<strong>输入:</strong>nums = [2,2,3,2]
<strong>输出:</strong>3
</pre>
 
<p><strong>示例 2:</strong></p>
 
<pre>
<strong>输入:</strong>nums = [0,1,0,1,0,1,99]
<strong>输出:</strong>99
</pre>
 
<p>&nbsp;</p>
 
<p><strong>提示:</strong></p>
 
<ul>
	<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>
	<li><code>-2<sup>31</sup> &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>
	<li><code>nums</code> 中,除某个元素仅出现 <strong>一次</strong> 外,其余每个元素都恰出现 <strong>三次</strong></li>
</ul>
 
 
 
---
 
[提交记录](https://leetcode.cn/problems/single-number-ii/submissions/) | [题解](https://leetcode.cn/problems/single-number-ii/solution/)
 
 

Solutions & Notes

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