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Description
tab: English
<p>Given the <code>root</code> of a binary tree, return <em>the bottom-up level order traversal of its nodes' values</em>. (i.e., from left to right, level by level from leaf to root).</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/02/19/tree1.jpg" style="width: 277px; height: 302px;" />
<pre>
<strong>Input:</strong> root = [3,9,20,null,null,15,7]
<strong>Output:</strong> [[15,7],[9,20],[3]]
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> root = [1]
<strong>Output:</strong> [[1]]
</pre>
<p><strong class="example">Example 3:</strong></p>
<pre>
<strong>Input:</strong> root = []
<strong>Output:</strong> []
</pre>
<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li>The number of nodes in the tree is in the range <code>[0, 2000]</code>.</li>
<li><code>-1000 <= Node.val <= 1000</code></li>
</ul>
---
[submissions](https://leetcode.com/problems/binary-tree-level-order-traversal-ii/submissions/) | [solutions](https://leetcode.com/problems/binary-tree-level-order-traversal-ii/solutions/)
tab: 中文
<p>给你二叉树的根节点 <code>root</code> ,返回其节点值 <strong>自底向上的层序遍历</strong> 。 (即按从叶子节点所在层到根节点所在的层,逐层从左向右遍历)</p>
<p> </p>
<p><strong>示例 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/02/19/tree1.jpg" style="width: 277px; height: 302px;" />
<pre>
<strong>输入:</strong>root = [3,9,20,null,null,15,7]
<strong>输出:</strong>[[15,7],[9,20],[3]]
</pre>
<p><strong>示例 2:</strong></p>
<pre>
<strong>输入:</strong>root = [1]
<strong>输出:</strong>[[1]]
</pre>
<p><strong>示例 3:</strong></p>
<pre>
<strong>输入:</strong>root = []
<strong>输出:</strong>[]
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li>树中节点数目在范围 <code>[0, 2000]</code> 内</li>
<li><code>-1000 <= Node.val <= 1000</code></li>
</ul>
---
[提交记录](https://leetcode.cn/problems/binary-tree-level-order-traversal-ii/submissions/) | [题解](https://leetcode.cn/problems/binary-tree-level-order-traversal-ii/solution/)
Solutions & Notes
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